Dilute a solution
How much concentrated solution and how much water you need to lower a concentration (C1·V1 = C2·V2).
Tool
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How it is calculated
The amount of solute does not change when water is added, so C1 × V1 = C2 × V2. Solving: V1 = C2 × V2 ÷ C1, and the water is V2 − V1.
Example: 70 % alcohol from 96 % alcohol, 1 L final. V1 = 70 × 1 ÷ 96 = 0.729 L of 96 % alcohol; water ≈ 1 − 0.729 = 0.271 L.
Example: 5 L of a 1 % solution from a 10 % one. V1 = 1 × 5 ÷ 10 = 0.5 L; water = 4.5 L. The dilution factor is 10 ÷ 1 = 10 times.
Recommended method: measure V1 in a graduated cylinder or marked container and add water up to the final-volume mark, instead of adding the two volumes separately.
Keep in mind
- Both concentrations must be in the same unit. Do not mix % v/v (volume) with % w/w (weight): alcohol is sold in % v/v and the calculation is valid in that unit.
- Ethanol and water contract when mixed: 0.729 L of 96 % alcohol plus 0.271 L of water give slightly less than 1 L, and the strength ends up slightly above 70 %. Filling up to the final volume corrects this; if the strength matters, measure it with an alcoholmeter at 20 °C.
- With concentrated acids, always add the acid to the water, little by little and stirring, never water to acid: the heat of dilution can boil the water and spatter acid. Goggles, gloves and a heat-resistant container.
- Do not mix bleach (hypochlorite) with acids (hydrochloric acid, vinegar) or with ammonia: they release chlorine or chloramines, toxic gases.
- To dilute more than 100 times it is more accurate to do it in two steps (for example, 1:10 and then 1:10 again) than to measure a very small volume.