Water and food for a group
Total water, energy and kilograms of a staple food to feed a group for several days.
Tool
Tools › Water and food
How it is calculated
Water (L) = people × days × L per person per day. Energy (kcal) = people × days × kcal per person per day. Food (kg) = energy × share (%) ÷ 100 ÷ kcal per kg.
Example. 10 people, 30 days, 15 L and 2100 kcal; wheat provides 70 %: water 10 × 30 × 15 = 4500 L; energy 10 × 30 × 2100 = 630 000 kcal; wheat 630 000 × 0.70 ÷ 3300 = 133.6 kg, that is 133 600 g ÷ 300 = 445 g per person per day.
Repeat the calculation for each food in the ration (for example, 70 % cereal, 15 % pulses, 15 % oil) and check that the shares add up to 100 %.
Keep in mind
- Energy of raw or dry food from composition tables (USDA; FAO): wheat 3270-3400 kcal/kg depending on variety; white rice 3600-3650; maize 3650; dry pulses 3300-3800 (bean 3330, lentil 3520, chickpea 3780); potato 770; oil 8840; sugar 3870.
- This tool only counts energy. A single-cereal diet falls short of quality protein, vitamins and minerals: combine cereal and pulses and add vegetables, fruit or fresh foods as soon as possible.
- Add a 10-20 % margin for storage losses (moisture, insects, rodents) and wasted rations.
- Children, pregnant and breastfeeding women, the sick and people doing hard work have different needs: 2100 kcal is a population average, not an individual figure. For malnutrition, consult health workers.
See also
Related articles
- Chemical disinfection of water with chlorine and iodine — Bleach, calcium hypochlorite and iodine doses per liter and per tank, contact times, residual chlorine, limits and safe handling.